How many different types of genetically different gametes will be produced by a heterozygous plant having the genotype AABb Ccdd ?

Options

A. Two
B. Four
C. Eight
D. Sixteen

Answer

To determine how many different types of genetically different gametes will be produced by a heterozygous plant with the genotype AABbCcdd, we can follow these steps:

### Step 1: Identify the genotype
The genotype given is AABbCcdd. We need to analyze each part of this genotype to find out how many traits are heterozygous.

### Step 2: Classify the alleles
- **AA**: Homozygous dominant (not heterozygous)
- **Bb**: Heterozygous
- **Cc**: Heterozygous
- **dd**: Homozygous recessive (not heterozygous)

### Step 3: Count the heterozygous traits
From the classification:
- Heterozygous traits: Bb and Cc
- Total heterozygous traits (n) = 2

### Step 4: Use the formula for gamete production
The number of different types of genetically different gametes produced by an individual is given by the formula:
\[ \text{Number of gametes} = 2^n \]
where \( n \) is the number of heterozygous traits.

### Step 5: Calculate the number of gametes
Substituting the value of \( n \):
\[ \text{Number of gametes} = 2^2 = 4 \]

### Conclusion
The heterozygous plant with the genotype AABbCcdd will produce **4 different types of genetically different gametes**.

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