The ratio of methane, ammonia and hydrogen is Stanley Miller's experiment was

Options

A. `3:1:2`
B. `2:1:2`
C. `1:2:1`
D. `5:4:1`

Answer

To solve the question regarding the ratio of methane, ammonia, and hydrogen in Stanley Miller's experiment, we can follow these steps:

### Step 1: Identify the components used in the experiment
In Stanley Miller's experiment, the primary gases used were:
- Methane (CH₄)
- Ammonia (NH₃)
- Hydrogen (H₂)

### Step 2: Determine the percentages of each gas
According to the information provided:
- The percentage of Methane (CH₄) was 2%.
- The percentage of Ammonia (NH₃) was 1%.
- The percentage of Hydrogen (H₂) was 2%.

### Step 3: Write down the percentages in ratio form
From the percentages, we can express the ratio of the gases:
- Methane: 2%
- Ammonia: 1%
- Hydrogen: 2%

### Step 4: Simplify the ratio
To express the ratios in the simplest form, we can write:
- Methane: 2
- Ammonia: 1
- Hydrogen: 2

Thus, the ratio of Methane:Ammonia:Hydrogen can be written as:
\[ 2:1:2 \]

### Step 5: Conclusion
The final answer is that the ratio of methane, ammonia, and hydrogen in Stanley Miller's experiment is **2:1:2**.

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