How many meiotic divisions are required to produce 104 male gametes in a typical Angiospermic plant ?

Options

A. 25
B. 26
C. 51
D. 13

Answer

To determine how many meiotic divisions are required to produce 104 male gametes in a typical Angiospermic plant, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Process of Meiosis in Angiospermic Plants**:
- In angiospermic plants, male gametes are produced from microspores through the process of meiosis.

2. **Identify the Outcome of One Meiotic Division**:
- Each meiotic division results in the formation of 4 microspores. This is crucial because it tells us how many gametes are produced from one division.

3. **Calculate the Number of Meiotic Divisions Needed**:
- To find out how many meiotic divisions are needed to produce 104 male gametes, we can use the formula:
\[ \text{Number of male gametes} = \text{Number of meiotic divisions} \times 4 \]
- Rearranging this gives us:
\[ \text{Number of meiotic divisions} = \frac{\text{Number of male gametes}}{4} \]

4. **Substitute the Given Number of Male Gametes**:
- We know we need 104 male gametes:
\[ \text{Number of meiotic divisions} = \frac{104}{4} = 26 \]

5. **Conclusion**:
- Therefore, to produce 104 male gametes, 26 meiotic divisions are required.

### Final Answer:
- **26 meiotic divisions are required to produce 104 male gametes in a typical Angiospermic plant.**

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