1-(sin^(2)y)/(1+cos y)+(1+cos y)/(sin y)-(sin y)/(1-cos y)=

1-(sin^(2)y)/(1+ cos y) + (1+ cosy)/( sin y) - (siny)/(1- cos y) =

If (cos^(4)x)/(cos^(2)y)+(sin^(4)x)/(sin^(2)y)=1 , then (cos^(4)y)/(cos^(2)x)+(sin^(4)y)/(sin^(2)y) equal :

If (cos^4x)/(cos^2y)+(sin^4x)/(sin^2y)=1,"show taht", (cos^4y)/(cos^2x)+(sin^4y)/(sin^2x)=1

If tan A=(x sin B)/(1-cos B)tan B=(y sin A)/(1-y cos A) then (x)/(y)=

Find the area bounded by the curves y=(sin^(-1)(sin x)+cos^(-1)(cos x)) and y=(sin^(-1)(sin x)+cos^(-1)(cos x))^(2) for 0<=x<=2 pi

Draw the graph of following function y = cos ^ (- 1) (cos x) y = sin ^ (- 1) (sin x) y = cos (cos ^ (- 1) x) y = sin (sin ^ (- 1) x)

If (cos ^ (4) x) / (cos ^ (2) y) + (sin ^ (4) x) / (sin ^ (2) y) = 1 then prove that (cos ^ (4) y) / (cos ^ (2) x) + (sin ^ (4) y) / (sin ^ (2) x) = 1

The value of (sin x cos y + cos x sin y)^2+(cos x cos y -sin x sin y)^2 is equal to

If (sin x) (sin y) = 1, then (cos x) (cos y) =?

If F(x)=[("cos"x,-sin x,0),(sin x,cos x,0),(0,0,1)] and G(y)=[(cos y,0,sin y),(0,1,0),(-sin y,0,cos y)] , then [F(x) G(y)]^(-1) is equal to