" The area bounded by the curve "f(x)-x+sin x" and its inverse function between ordinates "x-0" & "

Find the area bounded by the curve f(x)=x+ sin x and its inverse function between the ordinates x=0" to "x=2pi .

Find the area bounded by the curve f(x)=x+ sin x and its inverse function between the ordinates x=0" to "x=2pi .

Find the area bounded by the curve f(x)=x+ sin x and its inverse function between the ordinates x=0" to "x=2pi .

The area bounded by the curve f(x)=x+sin x and its inverse function between the ordinates x=0 and x=2 pi is (A) 4 pi square units (B) 8 pi square units (C) 4 square units (D) 8 square units

The area bounded by the curve y=(x-1)(x-2)(x-3) and x -axis lying between the ordinates x = 0 and x = 4 is

The area bounded by the curve y=(x-1)(x-2)(x-3) and X-axis lying between ordinates x=0 and x=3 is

The area bounded by the curve y=(x-1)(x-2)(x-3) and x -axis lying between the ordinates x=0 and x=4 is

Find the area bounded by the curve y=(x-1)(x-2)(x-3) and X-axis lying between ordinates x=0 and x=3

The area bounded by the curves y=cos x and y=sin x between the ordinates x=0 and x=3/2pi is: