sin^(6)theta+cos^(6)theta=1-3sin^(2)theta cos^(2)theta

sin^(6)theta+cos^(6)theta=1-3sin^(2)thetacos^(2)theta

sin^(6)theta=cos^(6)theta=1-3sin^(2)thetacos^(2)theta

sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1

Prove that sin^(6)theta+cos^(6)theta+3sin^(2)thetacos^(2)theta=1

Prove that cos^(6)theta+sin^(6)theta=1-3sin^(2)theta cos^(2)theta

The value of the expression sin^(6)theta+cos^(6)theta+3sin^(2)theta*cos^(2)theta equals

The value of sin^(8)theta+cos^(8)theta+sin^(6)theta cos^(2)theta+3sin^(4)theta cos^(2)theta+cos^(6)theta sin^(2)theta+3sin^(2)thetacos^(4)theta is equal to

The value of sin^(8)theta+cos^(8)theta+sin^(6)theta cos^(2)theta+3sin^(4)theta cos^(2)theta+cos^(6)theta sin^(2)theta+3sin^(2)thetacos^(4)theta is equal to

int(sin^(6)theta+cos^(6)theta)/(sin^(2)theta cos^(2)theta)d theta=

Prove the following identities: 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+1=0sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1(sin^(8)theta-cos^(8)theta)=(sin^(2)theta-cos^(2)theta)(1-2sin^(2)theta cos^(2)theta)