root(3)(216)

Find the simplest RF of : (a) root(4)(216) and (b) root(5)(16)

The following are the steps involved in finding the greatest among root(3)(2),root(6)(3) and sqrt(6) . Arrange them in sequential order. (A) The LCM of the denominators of the exponents is 6. (B) therefore root(6)(216) i.e., sqrt(6) is greatest. (C) root(3)(2)=2^(1//3), root(6)(3)=3^(1//6), sqrt(6)=6^(1//2) (D) 2^(1//3)=2^(2//6), 3^(1//6), 6^(1//2)=6^(3//6) (E) root(3)(2)=root(6)(4)root(6)(3)-root(6)(3),sqrt(6)=root(6)(216)

Evaluate root3(-216)

Evaluate root3(216) .

root3(1.728)/root3(13.824)xxroot3(4.096)/root3(216)=

Evaluate (i) root3((216)/(2197)) (ii) root3((-125)/(512))

(root3(1.728)-root3(0.216))/(root3(2.197)-root3(0.343))=