[" 2) "2x+y-35=0],[3x+4y-65=0]

Solve the following system of equations by using the method of cross-multiplication: 2x+y-35=0,\ \ \ \ 3x+4y-65=0

Solve the following system of equations by using the method of cross-multiplication: 2x+y-35=0,quad 3x+4y-65=0

The area of the parallelogram formed by lines 2x-y+3=0, 3x+4y-6=0,2x-y+9=0, 3x+4y+4=0 is (in sq units)

[" 16.A ray travelling along the line "3x-4y=5" after being reflected from a line " "Y" travels along the line "],[5x+12y=13" .Then the equation of the line "'l" is "],[[" 1) "x+8y=0," 2) "x-8y=0," 3) "32x+4y+65=0," 4) "32x-4y+65=0]]

Solve for x and y - 2x+3y-8=0 3x+4y-5=0

solve for x and y 2x-3y+7=0 3x+4y-5=0

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Let (2,3) be the focus of a parabola and x + y = 0 and x-y= 0 be its two tangents. Then equation of its directrix will be (a) 2x - 3y = 0 (b) 3x +4y = 0 (c) x +y = 5 (d) 12x -5y +1 = 0

The lines x+2y-5=0, 2x-3y+4=0,6x+4y-13=0