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A stone is released from the top of a cl...

A stone is released from the top of a cliff .Another particles is simultaneously projected `v=10 m/sec` from the bottom of the cliff if they meet after 2 second find the height of the cliff.

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To find the height of the cliff from which a stone is released and where another particle is projected upwards, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: - A stone is released from the top of a cliff (initial velocity \( u_1 = 0 \)). - Another particle is projected upwards from the bottom of the cliff with an initial velocity \( u_2 = 10 \, \text{m/s} \). - They meet after \( t = 2 \, \text{s} \). ...
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