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A cricketer of height 2.5 m thrown a bal...

A cricketer of height `2.5 m` thrown a ball at an angle of `30^(@)` with the horizontal such that it is received by another crickerter of same height standing at distance of `50m` from the first one.Find the maximum height attained by the ball.

Text Solution

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Let the ball rise to an additional height H. the disatnce between the crickter is equal to R =50 m The angle of projection `theta_030^(@)`, we know that
`tan theta_0=(4H)/(R )`
`implies tan 30^(@)=(4H)/(50)`
`implies H=(50)/(4sqrt(3))cong7.2m`
Therefore the maximum height attained by the ball
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