A body thrown at an angle `alpha` to the horizontal with some velocity.Assuming air drag to be negligible find the value of `alpha` so that horizontal range and maximum hieght of ascent are equal.

Explanation

To solve the problem of finding the angle \( \alpha \) such that the horizontal range and maximum height of a projectile are equal, we can follow these steps:

### Step 1: Understand the components of the initial velocity
When a body is thrown at an angle \( \alpha \) with an initial velocity \( u \):
- The horizontal component of the velocity \( u_x = u \cos \alpha \)
- The vertical component of the velocity \( u_y = u \sin \alpha \)

### Step 2: Write the formula for horizontal range
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