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A particle starts moving with a constant...

A particle starts moving with a constant angular acceleration in a circular path. The time at which the magnitudes of tangential and radial acceleration are equal is

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Let the speed of the particle of the particle after time t from starting be v
`implies` the centripetal acceleration, `a,=(V^2)/( r)=r omega^2` & the corresponding angular speed `omega=aplhat`
`implies a_1=r(alphat)^(2)=r alpha^2t^2`
We know that the tangential acceleration `a_1=r alpha` since `a_1=a_1` (given)
`impliesr alpha^2t^2=r alpha`
`impliest=(1)/(sqrt(alpha))`
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