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A point moves with decleration along the...

A point moves with decleration along the circle of radius R so that at any moment of time its tangential and normal accelerations
are equal in moduli. At the initial moment `t=0` the velocity of the point equals `v_0`. Find:
(a) the velocity of the point as a function of time and as a function of the distance covered `s_1`,
(b) the total acceleration of the point as a function of velocity and the distance covered.

Text Solution

Verified by Experts

The correct Answer is:
`v=(v_(0))/(1+(V_(0))/(R)t);v=v_(0)e^(-S//R)`
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