Home
Class 12
PHYSICS
A particle (P) is projected at an angle ...

A particle (P) is projected at an angle of `82^(@)` from horizontal with a velocity `6sqrt2 m//s` from the bottom of an inclined plane, having angle of inclination `37^(@)` At the same instant, another particle: Q is released from a heighth on a smooth incline plane. If after some time both particles collide, then find the
(a) value of time after which they collide,
(b) the height h

Text Solution

Verified by Experts

The correct Answer is:
(a) 1.5 sec (b) 5.4 m
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE) LEVEL-I|45 Videos
  • KINEMATICS

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE) LEVEL-I (ASSERTION REASONING TYPE)|2 Videos
  • KINEMATICS

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (SUBJECTIVE) LEVEL-I (Numerical)|8 Videos
  • HEAT AND TEMPERATURE

    FIITJEE|Exercise NUMERICAL BASES QUESTIONS|1 Videos
  • LAWS OF MOTION

    FIITJEE|Exercise COMPREHENSION-III|2 Videos

Similar Questions

Explore conceptually related problems

A particle is projected from the bottom of an inclined plane of inclination 30^@ . At what angle alpha (from the horizontal) should the particle be projected to get the maximum range on the inclined plane.

A particle is projected with a certain velocity at an angle alpha above the horizontal from the foot of an inclined plane of inclination 30^(@) . If the particle strikes the plane normally then alpha is equal to

A particle is projected with a certain velocity at an angle prop above the horizontal from the foot of an inclined plane of inclination 30^@ . If the particle strikes the plane normally, then prop is equal to.

A particle is projected horizontally with a speed V=5m/s from the top of a plane inclined at an angle theta=37^(@) to the horizontal (g=10m//s^(2)) What is the velocity of the particle just before it hits the plane?

A block is released from top of a smooth inclined plane.It reaches the bottom of the plane in 6 sec.The time taken by the body to cover the first half of the inclined plane is:

A particle is projected horizontally with a speed V=5m/s from the top of a plane inclined at an angle theta=37^(@) to the horizontal (g=10m//s^(2)) How far from the point of projection will the particle strike the plane?

A particle is projected horizontally with a speed V=5m/s from the top of a plane inclined at an angle theta=37^(@) to the horizontal (g=10m//s^(2)) Find the time taken by the particle to hit the plane.

A particle is projected with a velocity of 20 m/s at an angle of 30^(@) to an inclined plane of inclination 30^(@) to the horizontal. The particle hits the inclined plane at an angle 30^(@) , during its journey. The time of flight is -