The angle of which the velocity vector o...

The angle of which the velocity vector of a projectile thrown with a velocity u at an angle `theta` to the horizontal will take with the horizontal after time t of its being thrown up is

`theta`

`tan^(-1)((theta)/(t))`

`tan^(-1)((v cos theta)/(v sin theta-gt))`

`tan^(-1)((v sin theta-gt)/(v cos theta))`

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