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A block of mass m = 0.1 kg is released f...

A block of mass m = 0.1 kg is released from a height of 4 m on a curved smooth surface. On the horizontal surface, path AB is smooth and path BC offers coefficient of friction `mu = 0.1`. If the impact of block with the vertical wall at C be perfectely elastic, the total distance covered by the block on the horizontal surface before coming to rest will be (take `g = 10 ms^(–2)`) -

Text Solution

Verified by Experts

KE attained by block at `B=mgh=4J`
Work done by friction force on path `BC=(-mu mg)(BC)=-0.2J`
On the other horizontal surface block can make total forward and backward `((4)/(0.2))=20` trips.
But last time it will stop at B
`:.` Distance covered `=20xx(AB+BC)-AB=59m`.
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