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The energy needed for breaking a drop of...

The energy needed for breaking a drop of radius R into n drops each of radius r is

A

`(4pir^(2)-4piR^(2))T`

B

`(4piR^(2)-4pir^(2))T`

C

`[4/3pir^(3)-4/3piR^(3)]T`

D

`(4pir^(2)-n4pir^(2))//T`

Text Solution

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The correct Answer is:
A
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