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A body is orbitting around the earth at ...

A body is orbitting around the earth at mean radius `9` times as great as the orbit of a geostationary satellite to how many days it will complete one revolution around the earth and what is its angular velocity ?

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To solve the problem, we need to determine the time period of a body orbiting the Earth at a mean radius that is 9 times the radius of a geostationary satellite, and then calculate its angular velocity. ### Step-by-Step Solution: 1. **Identify the Mean Radius of the Geostationary Satellite**: - Let the mean radius of the geostationary satellite be \( R_1 \). - The mean radius of the body in question is \( R_2 = 9R_1 \). ...
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Knowledge Check

  • A body is orbiting around earth at a mean radius which is two times as greater as the parking orbit of a satellite, the period of body is

    A
    4 days
    B
    16 days
    C
    `2 sqrt(2)` days
    D
    64 days

  • The Moon completes one revolution around the Earth in ___ days.

    A
    27.3
    B
    28
    C
    30
    D
    22

  • Earth completes one orbit around the sun is

    A
    365 days 5 hrs 48 min and 46 sec
    B
    365 days 1 hrs 22 min and 3 sec
    C
    364 days 22 hrs 58 min and 39 sec
    D
    364 days 23 hrs 48 min and 51 sec

    • Similar Questions

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    A satellite is orbiting around the earth at a mean radius of 16 times that of the geostationary orbit. What is the period of the satellite ?

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    A satellite is orbiting around earth at a mean radius which is equal to two times as that as parking orbit of a satellite, the period of body is

    The mean radius of the orbit of a satellite is 4 times as great as that of the parking orbit of the earth. Then its period of revolution around the earth is

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