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The gravitational field strength vecE an...

The gravitational field strength `vecE` and gravitational potential `V` are releated as
`vecE=-((deltaV)/(deltax)hati+(deltaV)/(deltay)hatj+(deltaV)/(deltaz)hatk)`

In the figure, transversal lines represent equipotential surfaces. A particle of mass `m` is released from rest at the origin. The gravitational unit of potential , `1vecV=1cm^(2)//s^(2)`
Speed of the particle `(v)` (`y` is in cm and v in cm/s) as function of its `y`-co-ordinate is

A

`v=2sqrt(y)`

B

`v=sqrt(2)y`

C

`v=2y`

D

`v=2y+4y^(2)+2y^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
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