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The gravitational field strength vecE an...

The gravitational field strength `vecE` and gravitational potential `V` are releated as
`vecE=-((deltaV)/(deltax)hati+(deltaV)/(deltay)hatj+(deltaV)/(deltaz)hatk)`

In the figure, transversal lines represent equipotential surfaces. A particle of mass `m` is released from rest at the origin. The gravitational unit of potential , `1vecV=1cm^(2)//s^(2)`
`x`-component of the velocity of the particle at the point `(4cm, 4cm)` is

A

`4cm//s`

B

`2cm//s`

C

`2sqrt(2)(cm)/(s)`

D

`1cm//s`

Text Solution

Verified by Experts

The correct Answer is:
C
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