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Centripetal acceleration of a particle o...

Centripetal acceleration of a particle of mass m moving in a circle of radius r is `4//r^(2)`. What is the angular momentum of the particle ?

A

4 m/r

B

`4 m// sqrt(r)`

C

`2 m sqrt(r)`

D

2 m/r

Text Solution

Verified by Experts

The correct Answer is:
C
`a = (4)/(r^(2)) = (v^(2))/(r)`
`rArr" "v = sqrt((4)/(r))`
`L = mvr = m sqrt(4r) = 2m sqrt(r)`
Hence (C) is correct.
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