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An LC- circuit (inductance 0.01 H and ca...

An LC- circuit (inductance 0.01 H and capacitance `1 muF`) is connected to a variable a.c. source as shown in fig. 14.8. Draw rough sketch of the current -variation as the frequency is changed from 1 kHz to 2 kHz.

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We have,`|Z|=Z=sqrt(R^(2)+((1)/(omegaC-(1)/omegaL))^(2))`[refer to the solution of Fig. (b) in Question 11]At resonance, `omegaC =(1)/(LC) impliesZto infty`, and the current amplitude is `l_(o) =(V_(0)/(Z)=0`
Now,`f_(r)=(omega_(r))/(2pi)=(1)/(2pisqrt(LC))=(1)/(2pisqrt(0.01xx1xx10^(-6)))=1.592kHz`
So, for the given circuit`|Z|=(1)/(omegaC-(1)/(omegaL))=(1)/((2PIFC-(1)/(2pifL))`
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