Home
Class 12
PHYSICS
In an LCR series circuit the capacitance...

In an LCR series circuit the capacitance is changed from `C` to `4C` For the same resonant fequency the inductance should be changed from `L` to .

A

1//4

B

1//2

C

2L

D

4L

Text Solution

Verified by Experts

The correct Answer is:
A
`f=(1)/(2pi)sqrt((1)/(2))implies(1)/(L_(1)C_(1))=(1)/(L_(2)C_(2))`
`L_(2)=(L_(1)C_(1))/(C_(2))=(LxxC)/(4C)=(L)/(4)`
Promotional Banner

Topper's Solved these Questions

  • AC CIRCUITS

    FIITJEE|Exercise Exercise|3 Videos

  • AC CIRCUITS

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (SUBJECTIVE)(leve I)|10 Videos

  • AC CIRCUITS

    FIITJEE|Exercise SOLVED PROBLEMS (SUBJECTIVE)Prob|9 Videos

  • COLLISION

    FIITJEE|Exercise (NUMERICAL BASED QUESTIONS)|4 Videos

Similar Questions

Explore conceptually related problems

In a series resonant L-C-R circuit, the capacitance is changed from C to 3C. For the same resonant frequency, the inductance should be changed from L to

In an RLC circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to :

In a RLC circuit capacitance is changed from C to 2 C. For the resonant frequency to remain unchanged, the inductance should be changed from L to

in a LCR circuit capacitance is chagned from C to 2C. For the resomat frequency to remain unchaged, the inductance should be chagned from L to

In an L-C-R series, AC circuit at resonance

In LCR circuit, capacitor C is changed to 4C, then what should be the value of L to keep resonance frequency same

In an LCR a.c. circuit at resonance, the current

In an LCR circuit, the capacitance is made one-third, then what should be change in inductance, so that the circuit remains in resonance ?

An LCR series circuit contains L = 8 H, C = 0.5 muF and R =100 Omega The resonant frequency of the circuit is .