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For the circuit shown in fig, current in...

For the circuit shown in fig, current in inductance is 0.8A while that in capacitance is 0.6 A. What is the current drawn from the source?

Text Solution

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If an AC source `E = E_(0) sin omegat`
Current in inductance will lag the applied voltage while across the capacitor will lead.`I_(L)=(V)/(X_(L))sin(omegat-pi//2)`=`-0.8cosomegat` for inductor
`I_(c)=(V)/(X_(c))sin(omegat+pi/2)=+0.6cosomega` for capacitor
so current drawn from the source`I=I_(L)+I_(c)=-0.2cosomegat`
`I_(max)=|I_(0)|=0.2A`
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