Find `(dy)/(dx)` , if `x=costheta-cos2theta` , `y=sintheta-sin2theta`

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=costheta-cos2theta, y=sintheta-sin2theta

Find (dy)/(dx) , when x=costheta+cos2 theta,y=sin theta+sin2theta

Find dy/dx if x=costheta-cos2theta and y=sintheta-sin2theta

Find (d^2y)/(dx^2) : x = 2costheta - cos2theta, y = 2sintheta - sin2theta at theta = (pi)/2 .

Find (dy)/(dx) if x=cos theta - cos 2 theta and" "y = sin theta - sin 2theta

Find (dy)/(dx) if x=cos theta - cos 2 theta and" "y = sin theta - sin 2theta

Find (dy)/(dx) if x=cos theta - cos 2 theta and" "y = sin theta - sin 2theta

Find (dy)/(dx) if x= 3 cos theta - cos 2theta and y= sin theta - sin 2theta.

Find (dy)/(dx) if x= 3 cos theta - cos 2theta and y= sin theta - sin 2theta.

Find (dy)/(dx) if x=cos theta - cos 2 theta and" "y = sin theta - sin 2theta