" 42."x^(2)+5x-(a^(2)+a-6)=0

Solve x^(2)+5x-(a^(2)+a-6)=0 .

Solve x^(2)+5x-(a^(2)+a-6)=0 .

x^(2)-5x+6>0

Solve by the method of completing the square: (1) 9x^(2)-15x+6=0 (2) 5x^(2)-6x-2=0

Solve: (1-x^(2))/(5x-6-x^(2))<0

Find the value of k if the point (4,2) and (k,-3) are conjugate points with respect to the circles x^(2) + y ^(2) -5x +8y +6=0

Two non-integer roots of (x^(2) - 5x)^(2) - 7 (x^(2) - 5x) + 6 = 0 are

lim _( xto 2) ( x^(2) - 5x+ 6)/( x^(2) -4) ( ( 0 )/( 0 ) " form ")