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Find the locus of the point of intersect...

Find the locus of the point of intersection of the tangents to the ellipse `x^2/a^2+y^2/b^2=1(a> b)` if the difference of the eccentric angles of their points of contact is `2alpha.`

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The correct Answer is:
`(x^(2))/(a^(2))+(y^(2))/(b^(2))= sec^(2)alpha`
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