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If curve is represneted by C=21x^(2)-6xy...

If curve is represneted by `C=21x^(2)-6xy+29y^(2)-58y-151=0` then
The equation of major axis is

A

`x+3y+3=0`

B

`x+3y-3=0`

C

`x-3y+3=0`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the major axis of the given curve represented by \( C = 21x^2 - 6xy + 29y^2 - 58y - 151 = 0 \), we will follow these steps: ### Step 1: Identify the type of conic section The given equation is a quadratic in \(x\) and \(y\). To determine the type of conic, we need to calculate the discriminant \(D\) using the formula: \[ D = B^2 - 4AC \] where \(A = 21\), \(B = -6\), and \(C = 29\). ### Step 2: Calculate the discriminant Substituting the values: \[ D = (-6)^2 - 4 \cdot 21 \cdot 29 \] \[ D = 36 - 2436 = -2400 \] Since \(D < 0\), the conic section is an ellipse. ### Step 3: Rewrite the equation in standard form To find the axes of the ellipse, we need to rewrite the equation in the standard form of an ellipse: \[ \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \] We will first complete the square for the \(x\) and \(y\) terms in the equation. ### Step 4: Complete the square Rearranging the equation: \[ 21x^2 - 6xy + 29y^2 - 58y = 151 \] We can group the \(x\) and \(y\) terms: \[ 21x^2 - 6xy + 29(y^2 - 2y) = 151 \] Completing the square for \(y\): \[ y^2 - 2y = (y-1)^2 - 1 \] Substituting back: \[ 21x^2 - 6xy + 29((y-1)^2 - 1) = 151 \] This simplifies to: \[ 21x^2 - 6xy + 29(y-1)^2 - 29 = 151 \] \[ 21x^2 - 6xy + 29(y-1)^2 = 180 \] ### Step 5: Divide by 180 Now we divide the entire equation by 180 to get it into standard form: \[ \frac{21x^2 - 6xy + 29(y-1)^2}{180} = 1 \] ### Step 6: Identify the axes To find the major and minor axes, we need to identify the coefficients of \(x^2\) and \(y^2\) after rewriting the equation. The major axis is determined by the larger denominator in the standard form. ### Step 7: Determine the equation of the major axis From the standard form, we can determine the direction of the major axis. If \(a^2 > b^2\), the major axis is along the x-axis, and if \(b^2 > a^2\), the major axis is along the y-axis. In our case, we need to analyze the coefficients after completing the square and rewriting the equation. After simplifying, we find that the major axis is vertical, leading to the equation: \[ x = 0 \] ### Final Answer The equation of the major axis is: \[ x = 0 \]
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