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If the two means of regression are 4x+3y...

If the two means of regression are 4x+3y+7=0 and 3x+4y+8=0, then find the means of x and y.

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To find the means of \( x \) and \( y \) from the given regression equations, we will solve the two equations step by step. ### Step 1: Write down the given equations The two means of regression are given as: 1. \( 4x + 3y + 7 = 0 \) (Equation 1) 2. \( 3x + 4y + 8 = 0 \) (Equation 2) ### Step 2: Rearrange the equations We can rearrange both equations to express \( y \) in terms of \( x \). From Equation 1: \[ 3y = -4x - 7 \implies y = -\frac{4}{3}x - \frac{7}{3} \] From Equation 2: \[ 4y = -3x - 8 \implies y = -\frac{3}{4}x - 2 \] ### Step 3: Set the equations for \( y \) equal to each other Since both expressions represent \( y \), we can set them equal to find \( x \): \[ -\frac{4}{3}x - \frac{7}{3} = -\frac{3}{4}x - 2 \] ### Step 4: Clear the fractions To eliminate the fractions, we can multiply through by 12 (the least common multiple of 3 and 4): \[ 12 \left(-\frac{4}{3}x\right) - 12 \left(\frac{7}{3}\right) = 12 \left(-\frac{3}{4}x\right) - 12(2) \] This simplifies to: \[ -16x - 28 = -9x - 24 \] ### Step 5: Solve for \( x \) Now, we can bring all \( x \) terms to one side and constant terms to the other side: \[ -16x + 9x = -24 + 28 \] \[ -7x = 4 \implies x = -\frac{4}{7} \] ### Step 6: Substitute \( x \) back to find \( y \) Now that we have \( x \), we can substitute it back into either equation to find \( y \). We will use Equation 1: \[ 4\left(-\frac{4}{7}\right) + 3y + 7 = 0 \] \[ -\frac{16}{7} + 3y + 7 = 0 \] Convert 7 to a fraction: \[ -\frac{16}{7} + 3y + \frac{49}{7} = 0 \] Combine the constants: \[ 3y + \frac{33}{7} = 0 \] \[ 3y = -\frac{33}{7} \implies y = -\frac{11}{7} \] ### Final Answer Thus, the means of \( x \) and \( y \) are: \[ \text{Mean of } x = -\frac{4}{7}, \quad \text{Mean of } y = -\frac{11}{7} \]
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