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The coefficient of correlation between X...

The coefficient of correlation between X and Y is 0.6 U and V are two variables defined as `U=(x-3)/(2), V=(y-2)/(3)`, then the coefficient of correlation between U and V is

A

0.1

B

0.3

C

0.2

D

1

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The correct Answer is:
To find the coefficient of correlation between the variables U and V, we can use the following steps: ### Step 1: Understand the relationship between X, Y, U, and V We are given that the coefficient of correlation between X and Y is \( r_{XY} = 0.6 \). The variables U and V are defined as: \[ U = \frac{X - 3}{2} \] \[ V = \frac{Y - 2}{3} \] ### Step 2: Identify the transformation The transformations for U and V can be expressed in terms of X and Y: - U is a linear transformation of X (specifically, it is scaled and shifted). - V is a linear transformation of Y (also scaled and shifted). ### Step 3: Use the property of correlation coefficients The correlation coefficient remains unchanged under linear transformations. Specifically, if we have: \[ U = aX + b \quad \text{and} \quad V = cY + d \] then the correlation coefficient between U and V is given by: \[ r_{UV} = \frac{r_{XY}}{\sqrt{(a^2)(c^2)}} \] where \( a \) and \( c \) are the scaling factors of the transformations. ### Step 4: Identify the scaling factors From the definitions of U and V: - For U: \( a = \frac{1}{2} \) - For V: \( c = \frac{1}{3} \) ### Step 5: Calculate the coefficient of correlation between U and V Using the property of correlation coefficients: \[ r_{UV} = r_{XY} \cdot \frac{1}{\sqrt{(a^2)(c^2)}} \] Substituting the values: \[ r_{UV} = 0.6 \cdot \frac{1}{\sqrt{\left(\frac{1}{2}\right)^2 \cdot \left(\frac{1}{3}\right)^2}} \] Calculating the denominator: \[ \sqrt{\left(\frac{1}{2}\right)^2 \cdot \left(\frac{1}{3}\right)^2} = \sqrt{\frac{1}{4} \cdot \frac{1}{9}} = \sqrt{\frac{1}{36}} = \frac{1}{6} \] Thus: \[ r_{UV} = 0.6 \cdot \frac{1}{\frac{1}{6}} = 0.6 \cdot 6 = 3.6 \] ### Final Answer The coefficient of correlation between U and V is \( 3.6 \).
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