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Let s be the standard deviation of n obs...

Let s be the standard deviation of n observations. Each of the n observations is multiplied by a constant c. Then the standard deviation of the resulting number is

A

s

B

cs

C

`s sqrtc`

D

None of these

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the new standard deviation after multiplying each of the n observations by a constant \( c \). Let's break it down step by step. ### Step-by-Step Solution: 1. **Understanding Standard Deviation**: The standard deviation \( S \) of \( n \) observations \( a_1, a_2, a_3, \ldots, a_n \) is given by the formula: \[ S = \sqrt{\frac{1}{n} \sum_{i=1}^{n} (a_i - \bar{x})^2} \] where \( \bar{x} \) is the mean of the observations. 2. **New Observations**: When each observation is multiplied by a constant \( c \), the new observations become: \[ c \cdot a_1, c \cdot a_2, c \cdot a_3, \ldots, c \cdot a_n \] 3. **Calculating the New Mean**: The new mean \( \bar{x}' \) of the new observations is: \[ \bar{x}' = \frac{c \cdot a_1 + c \cdot a_2 + c \cdot a_3 + \ldots + c \cdot a_n}{n} = c \cdot \bar{x} \] This shows that the new mean is \( c \) times the old mean. 4. **New Standard Deviation Calculation**: The new standard deviation \( S' \) can be calculated using the new observations: \[ S' = \sqrt{\frac{1}{n} \sum_{i=1}^{n} (c \cdot a_i - \bar{x}')^2} \] Substituting \( \bar{x}' = c \cdot \bar{x} \): \[ S' = \sqrt{\frac{1}{n} \sum_{i=1}^{n} (c \cdot a_i - c \cdot \bar{x})^2} \] 5. **Factoring Out \( c \)**: We can factor \( c \) out of the expression: \[ S' = \sqrt{\frac{1}{n} \sum_{i=1}^{n} c^2 (a_i - \bar{x})^2} \] This simplifies to: \[ S' = c \cdot \sqrt{\frac{1}{n} \sum_{i=1}^{n} (a_i - \bar{x})^2} = c \cdot S \] 6. **Conclusion**: Therefore, the new standard deviation \( S' \) after multiplying each observation by \( c \) is: \[ S' = c \cdot S \] ### Final Answer: The standard deviation of the resulting numbers is \( c \cdot S \). ---
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