The entropy change in melting `1g` of ice at `0^@C`. (Latent heat of ice is `80 cal g^(-1)`)

Calculate the entropy change in the melting of 1 kg of ice at 0^(@)C in SI units. Heat of funsion of ice = 80 cal g^(-1) .

Calculate the entropy change in the melting of 1 kg of ice at 0^(@)C in SI units. Heat of funsion of ice = 80 cal g^(-1) .

Calculate change in entropy when 5g of pure ice melts to form water at 0^(@)C Given latent heat of ice is 80cal//g at 0^(@)C .

A coil of water of resistance 50 Omega is embedded in a block of ice and a potential difference of 210 V is applied across it. The amount of ice which melts in 1 second is [ latent heat of fusion of ice = 80 cal g^(-1) ]

A coil of water of resistance 50 Omega is embedded in a block of ice and a potential difference of 210 V is applied across it. The amount of ice which melts in 1 second is [ latent heat of fusion of ice = 80 cal g^(-1) ]

Calculate the amount of heat absorbed by 100 g of ice to change into water of 30^@ C.(Latent heat of fusion of ice is 80 cal//g )

22320 cal of heat is supplied to 100 g of ice at 0^(@)C . If the latent heat of fusion of ice is 80cal g^(-1) and latent heat of vaporization of water is 540cal g^(-1) , the final amount of water thus obtained and its temperature respectively are