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" (i) "(sin18^(@))/(cos72^(@))" ₹ at fिय...

" (i) "(sin18^(@))/(cos72^(@))" ₹ at fियान ? "

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(sin 18^@)/( cos 72 ^@) = ?

Evalute: (b) (sin18^(@))/(cos72^(@))

Evaluate: (sin18^(@))/(cos72^(@))

Evaluate: (i) (sin 18^(@))/(cos 72^(@))

Evaluate : (sin 18^(@))/(cos72^(@))

sin18^(@)-cos72^(@) is equal of :

Evaluate : (sin18^@)/(cos72^@) .

Prove that (sin18^(@))/(cos72^(@))=1

Evaluate : (sin 18^(@))/(cos 72^(@))