(sec theta+tan theta-1)/(tan theta-sec theta+1)

Simplify: tan theta[(sec theta, tan theta),(tan theta, -sec theta)] + sec theta[(- tan theta, -sec theta),(-sec theta, tan theta)] .

prove that (sec theta-tan theta-1)/(sec theta+tan theta-1)=tan theta-sec theta

Simplify sectheta[(sec theta,tan theta),(tan theta,sec theta)]-tan theta[(tan theta, sec theta),(sec theta, tan theta)]

The inverse of [(sec theta, - tan theta),(-tan theta, sec theta)] is

(tan theta+sec theta-1)/(tan theta-sec theta+1)

Show that ((tan theta+sec theta-1)/(tan theta-sec theta +1))=(1+sin theta)/(cos theta) .

Prove that (tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos theta)

(tan theta+sec theta-1)/(tan theta-sec theta+1)=(1+sin theta)/(cos theta)