The equation of the circle which touches the axes at a distances 5 from the origin is `y^(2) +x^(2) - 2alphax - 2alphay + alpha^(2) = 0`
What is the value of `alpha` ?

The greatest distance from (10, 7) to circle x^(2) + y^(2) - 4x - 2y - 20 = 0 is 5alpha unit, then the value of alpha is-

Equation of a circle which touches y-axis at (0,2) and cuts ff an intercept of 3 units from the x-axis is x ^(2) + y ^(2) - 2 alpha x -4y + 4=0 where alpha ^(2)=

The equation of the circle touching the y -axis at the origin is x^(2)+y^(2)-2ax=0. Find the differential equation of all such circles.

Equations of circles which touch both the axes and whose centres are at a distance of 2sqrt(2) units from origin are

Equations of circles which touch both the axes and whose centres are at a distance of 2sqrt(2) units from origin are

Equations of circles which touch both the axes and whose centres are at a distance of 2sqrt(2) units from origin are

Find the equation of a circle Which touches both the axes at a distance of 6 units from the origin.Which touches x-axis at a distance 5 from the origin and radius 6units Which touches both the axes and passes through the point (2,1) Passing through the origin,radius 17 and ordinate of the centre is -15.

Consider a circle (x-alpha)^(2)+(y-beta)^(2)=50 ,where alpha,beta>0 .If the circle touches the line y+x=0 at the point "P" ,whose distance from the origin is 4sqrt(2) ,then (alpha+beta)^(2) is equal to

An equation of a circle touching the axes of coordinates and the line x cos alpha+ y sin alpha = 2 can be