The value of `K_(c )` for the reaction `N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)` is `0.50` at `400^(@)C`. Find the value of `K_(p)` at `400^(@)C` when concentrations are expressed in mol `L^(-1)` and pressure in atm.
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Applying the relationship `K_p=K_c(RT)^(Deltan)` `K_c=0.50,R=0.082 "litre-atm" "deg"^(-1)mol^(-1)` `T(400+273)=673K,Deltan=(2-4)=-2` `K_p=0.5(0.082xx673)^(-2)` `=0.5(55.185)^(-2)=1.64xx10^(-4)`
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