When sulphur in the form of `S_8` is heated at 900k the initial pressure of 1 atm falls by 29% at equilibrium . This is because of conversion of some `S_8 "to" S_2` . Find the value of equilibrium constant for this reaction. `S_8(g) hArr 4S_2(g)`
Text Solution
AI Generated Solution
To solve the problem, we will follow these steps:
### Step 1: Understand the Reaction
The reaction given is:
\[ S_8(g) \rightleftharpoons 4S_2(g) \]
### Step 2: Initial Conditions
The initial pressure of \( S_8 \) is given as 1 atm. Therefore, we can denote:
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