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Equilibrium constant K(p) for H(2)S(g)...

Equilibrium constant `K_(p)` for
`H_(2)S(g) hArr 2H_(2)(g)+S_(2)(g)`
is `0.0118` atm at `1065^(@)C` and heat of dissociation is `42.4` Kcal. Find equilibrium constant at `1132^(@)C`.

Text Solution

Verified by Experts

`log_(10)=(K_(P_2))/(K_(P_1))=(DeltaH)/(2.303R)[(T_2-T_1)/(T_1T_2)]`
`rArr log_(10)""(K_(P_2))/(K_(P_1))=(42.4xx10^3)/(2.303xx2)[(1405-1338)/(1405xx1338)]`
`therefore (K_(P_2))/(K_(P_1))=2.129`
`K_(P_2)=2.129xx0.0118=0.025 "atm"`
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