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A sample of CaCO(3)(s) is introduced int...

A sample of `CaCO_(3)(s)` is introduced into a sealed container of volume `0.654 L` and heated to `1000 K` until equilibrium is reached. The equilibrium constant for the reaction
`CaCO_(3)(s)hArrCaO(s)+CO_(2)(g),`
is `3.9xx10^(-2)` atm at this temperature. Calculate the mass of `CaO` present at equilibrium.

Text Solution

Verified by Experts

`CaCO_3 (s) hArr CaO(s) +CO_2(g)`
`K_p=p_(CO_2)`
Let the number of moles of `CO_2` be formed =n
`n=(p_(CO_2)xxV)/(RT)=(3.9xx10^(-2)xx0.654)/(0.082 xx 1000)`
`=3.11 xx 10^(-4)` mol
The amount of CaO (s) formed will also be `=3.11 xx 10^(-4)` mol
Hence mass of CaO formed `=3.11 xx 10^(-4) xx 56 =0.0174 g`
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