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At 1000 k , the pressure of iodine gas ...

At 1000 k , the pressure of iodine gas is found to be 0.112 atm due to partial dissociation of `I_2 (g)` into I. Had there been no dissociation , the pressure would have been 0.074 atm. Calculate the value of `K_p` for the reaction, `I_2 (g) hArr 2I(g)`

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`K_p =0.16 atm`
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