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At 1000^@C the pressure of iodine gas i...

At `1000^@C` the pressure of iodine gas is found to be 0.112 atm whereas the expected pressure is 0.074 atm. The increased pressure is due to dissociation, `I_2 hArr 2I`. Calculate `K_p` . Also find out pressure at which `I_2` will be 90% dissociation at `1000^@C`.

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AI Generated Solution

To solve the problem, we need to calculate the equilibrium constant \( K_p \) for the dissociation of iodine gas and the pressure at which iodine will be 90% dissociated at \( 1000^\circ C \). ### Step 1: Write the balanced equation for the dissociation of iodine. The dissociation of iodine gas can be represented as: \[ I_2 \rightleftharpoons 2I \] ...
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