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The equilibrium constant of the reaction...

The equilibrium constant of the reaction `A_(2)(g)+B_(2)(g)hArr2AB(g)` at `100^(@)C` is 50. If a one litre flask containing one mole of `A_(2)` is connected to a two litre flask containing two moles of `B_(2)`, how many moles of `AB` will be formed at `373 K`?

A

1.86mol

B

0.93mol

C

1.00mol

D

2.00mol

Text Solution

Verified by Experts

The correct Answer is:
A
1.868
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