Home
Class 12
CHEMISTRY
For a reaction nA hArr Ab, degree of dis...

For a reaction `nA hArr A_b`, degree of dissociation when A trimerises is

A

`2((d-D)/d)`

B

`3/2((d-D)/d)`

C

`4/3((d-D)/d)`

D

`2((D-d)/d)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the degree of dissociation when A trimerizes in the reaction \( nA \rightleftharpoons A_b \), we can follow these steps: ### Step 1: Define the initial conditions Assume we start with 1 mole of A. Therefore, the initial concentration of A is 1 mole. ### Step 2: Define the degree of dissociation Let \( \alpha \) be the degree of dissociation. This means that at equilibrium, a fraction \( \alpha \) of A has dissociated. ### Step 3: Determine the changes in concentration When A trimerizes, it forms \( A_b \). For every 3 moles of A that react, 1 mole of \( A_b \) is produced. Therefore, if \( \alpha \) moles of A dissociate, the change in concentration can be expressed as: - Moles of A remaining: \( 1 - \alpha \) - Moles of \( A_b \) produced: \( \frac{\alpha}{3} \) ### Step 4: Calculate total moles at equilibrium The total moles at equilibrium can be calculated as: \[ \text{Total moles} = (1 - \alpha) + \frac{\alpha}{3} \] This simplifies to: \[ \text{Total moles} = 1 - \alpha + \frac{\alpha}{3} = 1 - \frac{2\alpha}{3} \] ### Step 5: Relate density to volume Density (\( D \)) is defined as mass per unit volume. The density before dissociation is inversely proportional to the volume. Thus, we can express the density before and after dissociation: - Before dissociation: \( D \propto \frac{1}{V} \) - After dissociation: \( d \propto \frac{1}{V(1 - \frac{2\alpha}{3})} \) ### Step 6: Set up the density ratio We can set up the ratio of densities before and after dissociation: \[ \frac{D}{d} = \frac{1}{1 - \frac{2\alpha}{3}} \] ### Step 7: Solve for \( \alpha \) Rearranging the equation gives: \[ d = D \cdot (1 - \frac{2\alpha}{3}) \] From this, we can express \( \alpha \) in terms of the densities: \[ \frac{D}{d} = 1 - \frac{2\alpha}{3} \] Solving for \( \alpha \): \[ \frac{D}{d} - 1 = -\frac{2\alpha}{3} \] \[ \alpha = \frac{3}{2} \left(1 - \frac{D}{d}\right) \] ### Conclusion The degree of dissociation \( \alpha \) when A trimerizes can be expressed in terms of the densities before and after the reaction.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE (LEVEL -I) REASONING TYPE QUESTIONS))|6 Videos
  • CHEMICAL EQUILIBRIUM

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE ( LEVEL -II))|20 Videos
  • CHEMICAL EQUILIBRIUM

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE)|3 Videos
  • CHEMICAL ENERGETICS

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS|2 Videos
  • CHEMICAL KINETICS AND RADIOACTIVITY

    FIITJEE|Exercise Exercise|9 Videos

Similar Questions

Explore conceptually related problems

For a reaction, 4A hArr 5B degree of dissociation is 10% at a pressure of 2 atm and 300 K.what will be approx degree of dissociation at 0.04 atm pressure and 300 K.

Degree of dissociation of weak electrolyte AB is

Degree OF dissociation||Extent OF reaction

For the reaction N_(2)O_(4)hArr 2NO_(2(g)), the degree of dissociation of N_(2)O_(4) is 0.2 at 1 atm. Then the K_(p) of 2NO_(2)hArr N_(2)O_(4) is

The equilibrium constant K_p for the reaction AhArr2B is related to the degree of dissociation (alpha) of A and total pressure P as

For the reaction 2AB(g)hArrA_(2)(g)+B_(2)(g) The degree of dissociation (alpha) of HI(g) is related to equilibrium constant K_(p) by the expression

Degree Of Association And Degree Of Dissociation

At temperature T, a compound AB_2(g) dissociation according to the reaction, 2AB _2(g) hArr 2AB(g) +B_2(g) with degree of dissociation, alpha , which is small compared to unity . Deduce the expression for alpha in terms of the equilibrium constant K_p and the total pressure P.

FIITJEE-CHEMICAL EQUILIBRIUM-ASSIGNMENT PROBLEMS (OBJECTIVE (LEVEL -I))
  1. For the reaction N2O4 hArr 2NO2 , if degrees of dissociation of N2O4 a...

    Text Solution

    |

  2. For the reaction, CaCO3 (s) to CaO(s) +CO2(g) , which is correct repre...

    Text Solution

    |

  3. The equation alpha =(D-d)/((n-1)d) is correctly matched for

    Text Solution

    |

  4. For a reaction nA hArr Ab, degree of dissociation when A trimerises is

    Text Solution

    |

  5. The equilibrium constant Kc for the reaction SO2 (g) +NO2(g) hArr SO(3...

    Text Solution

    |

  6. When a mixture of N2 and H2 in the volume ratio of 1:5 is allowed to ...

    Text Solution

    |

  7. For the reaction CO2(g) +H2 hArr CO(g) +H2O(g) The Kp for the reac...

    Text Solution

    |

  8. For the given reaction. 2A(s) +B(g) hArrC(g)+2D(s) +E(s) the degre...

    Text Solution

    |

  9. For the given equilibrium L((g)) hArr M((g)) The Kf =5xx10^(-4) mo...

    Text Solution

    |

  10. Given the standard enthalpies at 298 k in kj/mol for the following two...

    Text Solution

    |

  11. For the reaction: 2NOCI(g) hArr 2NO+CI2(g) ,Kc "at" 427^@C is 3xx 10^6...

    Text Solution

    |

  12. The partial pressure of CH3OH,CO and H2 in the equilibrium mixture for...

    Text Solution

    |

  13. One mole each of CH3CO2H and CH3CH2OH are heated in presence of little...

    Text Solution

    |

  14. 24 mL of HI are produced from the reaction of 15mL of H2 and 17.1 mL o...

    Text Solution

    |

  15. In the reaction A2(g) +4B2(g) hArr 2AB3(g) , DeltaH lt 0 . The decomp...

    Text Solution

    |

  16. In a system A(s) hArr 2B (g) +3C(g) if the conc. Of C at equilibrium...

    Text Solution

    |

  17. 2 mole of A (atomic weight =60 ) is taken in a 2 litre vessel which ...

    Text Solution

    |

  18. The equilibrium constant for the reaction, SO3(g)hArr SO2(g)+1/2O2(g...

    Text Solution

    |

  19. A 10 litre box contains O3 and O2 at equilibrium at 2000 k. Kp=4.17xx1...

    Text Solution

    |

  20. The equilibrium constant for the reaction N2(g) +O2(g) hArr 2NO(g) "is...

    Text Solution

    |