Calculate the number of atoms of oxygen present in 88 g of `CO_(2)`. What would be the weight of CO having the same number of oxygen atoms ?

Explanation

Mol wt. of `CO_(2) = 44`
lt has 32 g of `O_(2)` and one molecule of `O_(2)` has 2 atoms.
44 g of `CO_(2) = 2N ` atoms of O
` :. 88 " g of " CO_(2) = (2 xx 6.023 xx 10^(23) xx 88)/44 ` atoms of oxygen
` = 24.092 xx 10^(23)` atoms of oxygen.
Also, mol wt. of `CO = 28 ` and it has 16 g of oxygen and one atom of O in one molecule of CO
N atoms of O are present in 28 g CO
` :. 24 . 092 xx 10^(13)` atoms of oxygen are present ` = (28 xx 24.092 xx 10^(23))/(6.023 xx 10^(23)) = 112 ` g of CO