A sample of `CaCO_3` and `MgCO_3` weighed 2.21 g is ignited to constant weight of 1.152 g. What is the composition of mixture ? Also calculale the volume of `CO_2` evolved at `0^@C` and 76 cm of pressure.

Explanation

`{:(CaCO_(3) to CaO + CO_(2)),(xg),(MgCO_(3) to MgO + CO_(2)),(y g):}`
`x+ y = 2.21`
100 g of `CaCO_(3)` gives = 56 g of CaO
`:. ` x g of `CaCO_(3)` gives ` = (56 xx (x))/100 ` g of CaO
Similarly 84 g of `MgCO_(3)` gives = 40 g of MgO
` :. ` y g of `MgCO_(3) " gives " = (40 xx y)/84 g ` MgO