Find out the volume of `Cl_(2)` at STP produced by the action of 100 `cm^(3)` of `0.2N` HCl on excess of `MnO_(2)`.

Explanation

To find the volume of Cl₂ produced at STP by the action of 100 cm³ of 0.2N HCl on excess MnO₂, we can follow these steps:

### Step 1: Write the balanced chemical equation
The reaction between MnO₂ and HCl can be represented as:
\[ \text{MnO}_2 + 4 \text{HCl} \rightarrow \text{MnCl}_2 + 2 \text{H}_2\text{O} + \text{Cl}_2 \]
This indicates that 4 moles of HCl produce 1 mole of Cl₂.
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