Predict the molar ratio in which the following two substances would react ?
`Ba_(3)(PO_(4))_(2) " and " AlCl_(3)`.

Explanation

n-factor of `Ba_(3) (PO_(4)) = 3 xx (+2) = 6 = n_(1)`
While n-factor of `AlCl_(3) = 1 xx (+3) = 3 - n_(2)`
`n_(1)/n_(2) = 6/3`
If ` n_(1)/n_(2) = x/y `
Molar ratio = `y/x ` (inverse of equivalent ratio)
` :. ` Molar ratio in which `Ba_(3)(PO_(4))" and " AlCl_(3)` will react ` = 3.6 = 1 : 2`