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What weight of Na(2)CO(3) of 95% purity ...

What weight of `Na_(2)CO_(3)` of 95% purity would be required to neutralize `45.6 mL` of `0.235 N` acid?

A

`0.5978 `g

B

`5.978 `g

C

`0.05978 `g

D

`59.78 `g

Text Solution

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The correct Answer is:
A
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What weight of Na_(2)CO_(3) of 93% purity would be required to neutralise 45.6 mL of 0.235 N acid?

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