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The hydrated salt Na(2)SO(4).xH(2)O unde...

The hydrated salt `Na_(2)SO_(4).xH_(2)O` undergoes `55%` loss in weight on heating and becomes anhydrous. The value of x will be

A

5

B

3

C

7

D

10

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AI Generated Solution

The correct Answer is:
To solve the problem of determining the value of \( x \) in the hydrated salt \( Na_2SO_4 \cdot xH_2O \) that undergoes a 55% loss in weight upon heating, we can follow these steps: ### Step 1: Understand the Composition of the Hydrated Salt The hydrated salt is represented as \( Na_2SO_4 \cdot xH_2O \). This means that for every mole of sodium sulfate, there are \( x \) moles of water. ### Step 2: Calculate the Molar Mass of the Components 1. **Molar mass of \( Na_2SO_4 \)**: - Sodium (Na): \( 23 \, \text{g/mol} \times 2 = 46 \, \text{g/mol} \) - Sulfur (S): \( 32 \, \text{g/mol} \) - Oxygen (O): \( 16 \, \text{g/mol} \times 4 = 64 \, \text{g/mol} \) - Total: \( 46 + 32 + 64 = 142 \, \text{g/mol} \) 2. **Molar mass of water (\( H_2O \))**: - Hydrogen (H): \( 1 \, \text{g/mol} \times 2 = 2 \, \text{g/mol} \) - Oxygen (O): \( 16 \, \text{g/mol} \) - Total: \( 2 + 16 = 18 \, \text{g/mol} \) ### Step 3: Write the Total Molar Mass of the Hydrated Salt The total molar mass of the hydrated salt \( Na_2SO_4 \cdot xH_2O \) is: \[ \text{Total Molar Mass} = 142 + 18x \] ### Step 4: Calculate the Mass of Water Lost When heated, the hydrated salt loses \( x \) moles of water, which corresponds to a mass of: \[ \text{Mass of water lost} = 18x \, \text{g} \] ### Step 5: Set Up the Equation for Percent Loss We know that the percent loss in weight is given as 55%. Therefore, we can set up the equation: \[ \frac{\text{Mass of water lost}}{\text{Total mass of hydrated salt}} \times 100 = 55 \] Substituting the known values: \[ \frac{18x}{142 + 18x} \times 100 = 55 \] ### Step 6: Solve the Equation 1. Rearranging gives: \[ \frac{18x}{142 + 18x} = 0.55 \] 2. Cross-multiplying: \[ 18x = 0.55(142 + 18x) \] 3. Expanding: \[ 18x = 77.1 + 9.9x \] 4. Rearranging: \[ 18x - 9.9x = 77.1 \] \[ 8.1x = 77.1 \] 5. Solving for \( x \): \[ x = \frac{77.1}{8.1} \approx 9.56 \] ### Step 7: Round to the Nearest Whole Number Since \( x \) must be a whole number, we round \( 9.56 \) to \( 10 \). ### Final Answer The value of \( x \) is approximately \( 10 \). ---
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