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When Cl(2) is passed through hot NaOH , ...

When `Cl_(2)` is passed through hot NaOH , oxidation number of Cl changes from

A

`-1 " to " 0`

B

`0 " to " -1`

C

`0 " to " +5`

D

`0 " to " +7`

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The correct Answer is:
To determine the change in oxidation number of chlorine when \( Cl_2 \) is passed through hot sodium hydroxide (NaOH), we can analyze the reaction step by step. ### Step 1: Write the Reaction When chlorine gas (\( Cl_2 \)) is passed through hot NaOH, the products formed are sodium chloride (\( NaCl \)) and sodium chlorate (\( NaClO_3 \)). The balanced chemical equation for this reaction is: \[ Cl_2 + 2 NaOH \rightarrow NaCl + NaClO_3 + H_2O \] ### Step 2: Determine the Oxidation States Next, we need to determine the oxidation states of chlorine in the reactants and products. 1. **In \( Cl_2 \)**: The oxidation state of chlorine is 0 (as it is in its elemental form). 2. **In \( NaCl \)**: The oxidation state of chlorine is -1. This can be calculated as follows: - Sodium (Na) has an oxidation state of +1. - Therefore, for \( NaCl \): \( +1 + x = 0 \) where \( x \) is the oxidation state of Cl. Thus, \( x = -1 \). 3. **In \( NaClO_3 \)**: The oxidation state of chlorine can be calculated using the known oxidation states of sodium and oxygen: - Sodium (Na) has an oxidation state of +1. - Oxygen (O) has an oxidation state of -2. - For 3 oxygen atoms: \( 3 \times (-2) = -6 \). - Therefore, for \( NaClO_3 \): \( +1 + x - 6 = 0 \) where \( x \) is the oxidation state of Cl. Thus, \( x = +5 \). ### Step 3: Analyze the Change in Oxidation State Now we can summarize the changes in oxidation states: - Chlorine changes from 0 in \( Cl_2 \) to -1 in \( NaCl \) (reduction). - Chlorine changes from 0 in \( Cl_2 \) to +5 in \( NaClO_3 \) (oxidation). ### Step 4: Conclusion Thus, the oxidation number of chlorine changes from 0 to -1 (reduction) and from 0 to +5 (oxidation). This indicates that both reduction and oxidation occur in this reaction, making it a redox reaction. ### Final Answer The oxidation number of Cl changes from 0 to -1 in sodium chloride and from 0 to +5 in sodium chlorate. ---
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FIITJEE-STOICHIOMETRY AND BALANCING REDOX REACTION -ASSIGNMENT PROBLEMS (OBJECTIVE ) (Level - II)
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  16. Which of the following act both as an oxidising as well as reducing ag...

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  17. When Cl(2) is passed through hot NaOH , oxidation number of Cl changes...

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